If α, β are the roots of the equation 2x^2 + 3x + 5 = 0 , then the value of the determinant 0 & β & β \\ α & 0 & α \\ β & α & 0 is: - Mathematics MCQ Mathematics Mock Test - 9 2026 | ExamTest.live

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If α, β are the roots of the equation 2 x^{2} + 3 x + 5 = 0, then the value of the determinant 0 α β β 0 α β α 0 is:

Solution & Step-by-step Explanation

For 2 x^{2} + 3 x + 5 = 0 : α + β = - 3/2 α β = 5/2 .Evaluate the determinant: Δ = 0 (0 - α^{2}) - β (0 - α β) + β (α^{2} - 0) Δ = α β^{2} + α^{2} β = α β (α + β) .Substitute values: Δ = (\frac{5}{2}) (- \frac{3}{2}) = - \frac{15}{4} .

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If α, β are the roots of the equation 2 x^{2} + 3 x + 5 = 0, then the value of the determinant 0 α β β 0 α β α 0 is:

- 3/5

- 15/4

3/5

15/4

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