If cos2θ=0, where θ is an acute angle, then find the value of sin(75
∘
−θ).
- A2
2
+1
- B2
2
1
- C2
2
−1
- D2
1
Solution & Step-by-step Explanation
Given equation:
cos2θ=0
Since θ is an acute angle, 2θ must lie within a suitable principal range. We know that cos90
∘
=0.
2θ=90
∘
⟹θ=45
∘
Now substitute θ=45
∘
into the required expression:
sin(75
∘
−θ)=sin(75
∘
−45
∘
)=sin30
∘
We know that:
sin30
∘
=
2
1
Let's check alternative matching if standard typesetting indicates: If sin(75
∘
−θ) equals sin(30
∘
)=1/2, let us observe option D which stands as
2
1
or if expression was sin(15
∘
) or similar. Let's make sure if cos2θ=0⟹2θ=90
∘
⟹θ=45
∘
. Then sin(75
∘
−45
∘
)=sin30
∘
=
2
1
. If option D corresponds to
2
1
or
2
1
, let's double check alignment.
cos2θ=0
Since θ is an acute angle, 2θ must lie within a suitable principal range. We know that cos90
∘
=0.
2θ=90
∘
⟹θ=45
∘
Now substitute θ=45
∘
into the required expression:
sin(75
∘
−θ)=sin(75
∘
−45
∘
)=sin30
∘
We know that:
sin30
∘
=
2
1
Let's check alternative matching if standard typesetting indicates: If sin(75
∘
−θ) equals sin(30
∘
)=1/2, let us observe option D which stands as
2
1
or if expression was sin(15
∘
) or similar. Let's make sure if cos2θ=0⟹2θ=90
∘
⟹θ=45
∘
. Then sin(75
∘
−45
∘
)=sin30
∘
=
2
1
. If option D corresponds to
2
1
or
2
1
, let's double check alignment.