If cot(
2
A
)=x, then the value of x is:
- A1−cosA
1+cosA
- BcscA−cotA
- C2
1−cosA
- D2
1+cosA
Solution & Step-by-step Explanation
We know the standard half-angle trigonometric formulas:
cosA=2cos
2
(
2
A
)−1⟹1+cosA=2cos
2
(
2
A
)
cosA=1−2sin
2
(
2
A
)⟹1−cosA=2sin
2
(
2
A
)
Dividing the first equation by the second:
1−cosA
1+cosA
=
2sin
2
(
2
A
)
2cos
2
(
2
A
)
=cot
2
(
2
A
)
Taking the square root on both sides:
cot(
2
A
)=
1−cosA
1+cosA
Since x=cot(
2
A
), we get:
x=
1−cosA
1+cosA
cosA=2cos
2
(
2
A
)−1⟹1+cosA=2cos
2
(
2
A
)
cosA=1−2sin
2
(
2
A
)⟹1−cosA=2sin
2
(
2
A
)
Dividing the first equation by the second:
1−cosA
1+cosA
=
2sin
2
(
2
A
)
2cos
2
(
2
A
)
=cot
2
(
2
A
)
Taking the square root on both sides:
cot(
2
A
)=
1−cosA
1+cosA
Since x=cot(
2
A
), we get:
x=
1−cosA
1+cosA