If
cotB−cotA
cotAcotB+1
=x, then the value of x is:
- Acot(A+B)
- Bcot(A−B)
- Ctan(A−B)
- Dtan(A+B)
Solution & Step-by-step Explanation
By standard trigonometric identity, the formula for the cotangent of the difference of two angles is:
cot(A−B)=
cotB−cotA
cotAcotB+1
Comparing this with the given expression:
x=cot(A−B)
cot(A−B)=
cotB−cotA
cotAcotB+1
Comparing this with the given expression:
x=cot(A−B)