If
cscA−cotA
1
=x, then the value of x is:
- AcscA+cotA
- BcscA−cotA
- Ccsc
2
A+cot
2
A - Dcsc
2
A+cot
2
A
Solution & Step-by-step Explanation
We know the standard trigonometric identity:
csc
2
A−cot
2
A=1
This can be factored as:
(cscA−cotA)(cscA+cotA)=1
Rearranging the terms:
cscA−cotA
1
=cscA+cotA
Therefore, x=cscA+cotA.
csc
2
A−cot
2
A=1
This can be factored as:
(cscA−cotA)(cscA+cotA)=1
Rearranging the terms:
cscA−cotA
1
=cscA+cotA
Therefore, x=cscA+cotA.