If $\frac{1}{1+\cos A}+\frac{1}{1-\cos A}=x$, then the value of $x$ is:

Given expression:
$$x=\frac{1}{1+\cos A}+\frac{1}{1-\cos A}$$
Find a common denominator:
$$x=\frac{(1-\cos A)+(1+\cos A)}{(1+\cos A)(1-\cos A)}$$
Simplify the numerator and the denominator:
$$x=\frac{2}{1-{\cos }^{2}A}$$
Using the fundamental trigonometric identity $1-{\cos }^{2}A={\sin }^{2}A$:
$$x=\frac{2}{{\sin }^{2}A}$$
$$x=2{\csc }^{2}A$$