If $\frac{4}{x}<\frac{1}{3}$, what is the possible range of values for $x$?

Given:
$$\frac{4}{x}<\frac{1}{3}$$
$$\Rightarrow \frac{4}{x}-\frac{1}{3}<0$$
$$\Rightarrow \frac{12-x}{3x}<0$$
$$\Rightarrow \frac{x-12}{x}>0(\text{multiplying by }-1\text{ reverses the inequality})$$
The critical points are $x=0$ and $x=12$.For the expression to be positive:$x-12>0$ and $x>0\Rightarrow x>12$$x-12<0$ and $x<0\Rightarrow x<0$ Thus, the range is $x<0$ OR $x>12$.