If g is the acceleration due to gravity on the earth’s surface, the gain in the potential energy of object of mass m raised from the surface of the ea - Physics MCQ AIEEE 2004 2026 | ExamTest.live

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If g is the acceleration due to gravity on the earth’s surface, the gain in the potential energy of object of mass m raised from the surface of the earth to a height equal to the radius R of the earth is:

Solution & Step-by-step Explanation

Gain in potential energy Δ U = U_{f ina l} - U_{ini t ia l} . U = - \frac{GM m}{r} At surface r_{1} = R, at height h = R we have r_{2} = 2 R . Δ U = - \frac{GM m}{2 R} - (- \frac{GM m}{R}) = \frac{GM m}{R} (1 - \frac{1}{2}) = \frac{GM m}{2 R} Since GM = g R^{2} : Δ U = \frac{g R ^{2} m}{2 R} = \frac{1}{2} m g R

Try it yourself before checking the explanation above.

If g is the acceleration due to gravity on the earth’s surface, the gain in the potential energy of object of mass m raised from the surface of the earth to a height equal to the radius R of the earth is:

2 m g R

\frac{1}{2} m g R

\frac{1}{4} m g R

m g R

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