If in a certain code language, '$+$ ' represents '$\times$ ', '$-$ ' represents '$+$ ', '$\times$ ' represents '$÷$ ' and '$÷$ ' represents '$-$ ', find the answer to the following question:
$$4+2-9\times 3÷6=?$$

First, let's substitute the mathematical operators as per the given code instructions:
* Replace $+$ with $\times$
* Replace $-$ with $+$
* Replace $\times$ with $÷$
* Replace $÷$ with $-$

The expression becomes:

$$4\times 2+9÷3-6$$

Now, apply the BODMAS rule to solve it:

1. Division ($÷$):

$$9÷3=3⟹4\times 2+3-6$$

2. Multiplication ($\times$):

$$4\times 2=8⟹8+3-6$$

3. Addition ($+$) and Subtraction ($-$):

$$8+3=11⟹11-6=5$$