If M_O is the mass of an oxygen isotope ^17_8O , M_p and M_n are the masses of a proton and a neutron respectively, the nuclear binding energy of the - Physics MCQ AIEEE 2007 2026 | ExamTest.live

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If M_{O} is the mass of an oxygen isotope_{8}^{17} O, M_{p} and M_{n} are the masses of a proton and a neutron respectively, the nuclear binding energy of the isotope is:

Solution & Step-by-step Explanation

The mass defect Δ m is given by the difference between the mass of the individual nucleons and the mass of the nucleus.For_{8}^{17} O :Number of protons Z = 8 .Number of neutrons A - Z = 17 - 8 = 9 . Δ m = (8 M_{p} + 9 M_{n}) - M_{O} The binding energy is BE = Δ m \cdot c^{2} : BE = (8 M_{p} + 9 M_{n} - M_{O}) c^{2} Note: The solution provided in the text (M_{O} - 8 M_{p} - 9 M_{n}) c^{2} usually refers to the mass difference where the sign indicates energy released or mass deficit; the standard definition of Binding Energy is positive. Option B matches the standard magnitude.

Try it yourself before checking the explanation above.

If M_{O} is the mass of an oxygen isotope_{8}^{17} O, M_{p} and M_{n} are the masses of a proton and a neutron respectively, the nuclear binding energy of the isotope is:

(M_{O} - 8 M_{p}) c^{2}

(8 M_{p} + 9 M_{n} - M_{O}) c^{2}

M_{O} c^{2}

(M_{O} - 17 M_{n}) c^{2}

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