If N=(307)
38
+(524)
20
, then what is the unit digit of N?
- A6
- B5
- C3
- D4
Solution & Step-by-step Explanation
To find the unit digit of N, we find the unit digit of each individual term using the rules of cyclicity.
First Term: (307)
38
The unit digit depends only on the base's unit digit, which is 7.
The cyclicity of 7 is 4. Let's divide the exponent 38 by 4 to find the remainder:
38÷4=9 with a remainder of 2
Therefore, the unit digit of (307)
38
is the same as the unit digit of 7
2
=49, which is 9.
Second Term: (524)
20
The unit digit depends only on the base's unit digit, which is 4.
The pattern for the unit digit of 4
n
is:
4
1
=4 (odd powers end in 4)
4
2
=16 (even powers end in 6)
Since the exponent 20 is an even number, the unit digit of (524)
20
is 6.
Unit digit of N:
Unit Digit=9+6=15→5
First Term: (307)
38
The unit digit depends only on the base's unit digit, which is 7.
The cyclicity of 7 is 4. Let's divide the exponent 38 by 4 to find the remainder:
38÷4=9 with a remainder of 2
Therefore, the unit digit of (307)
38
is the same as the unit digit of 7
2
=49, which is 9.
Second Term: (524)
20
The unit digit depends only on the base's unit digit, which is 4.
The pattern for the unit digit of 4
n
is:
4
1
=4 (odd powers end in 4)
4
2
=16 (even powers end in 6)
Since the exponent 20 is an even number, the unit digit of (524)
20
is 6.
Unit digit of N:
Unit Digit=9+6=15→5