If O is the orthocentre of a ΔABC and ∠BOC=140
∘
, then the measure of ∠BAC is:
- A40
∘ - B60
∘ - C30
∘ - D45
∘
Solution & Step-by-step Explanation
In any triangle where O is the orthocentre (the intersection point of altitudes), the relationship between the angle formed at the orthocentre and the opposite vertex angle is given by:
∠BOC+∠BAC=180
∘
Given ∠BOC=140
∘
:
140
∘
+∠BAC=180
∘
∠BAC=180
∘
−140
∘
=40
∘
∠BOC+∠BAC=180
∘
Given ∠BOC=140
∘
:
140
∘
+∠BAC=180
∘
∠BAC=180
∘
−140
∘
=40
∘