If P(A) = 0.4 , P(B) = 0.8 , and P(B|A) = 0.6 , then P(A B) is equal to: - Mathematics MCQ Mathematics Mock Test - 1 2026 | ExamTest.live

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If P (A) = 0.4, P (B) = 0.8, and P (B ∣ A) = 0.6, then P (A \cup B) is equal to:

Solution & Step-by-step Explanation

We know P (B ∣ A) = \frac{P ( A \cap B )}{P ( A )} . 0.6 = \frac{P ( A \cap B )}{0.4} ⟹ P (A \cap B) = 0.24 Now find P (A \cup B) using the addition theorem: P (A \cup B) = P (A) + P (B) - P (A \cap B) P (A \cup B) = 0.4 + 0.8 - 0.24 = 1.2 - 0.24 = 0.96

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If P (A) = 0.4, P (B) = 0.8, and P (B ∣ A) = 0.6, then P (A \cup B) is equal to:

0.24

0.3

0.48

0.96

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