If price of an article decreases from Rs P
1
to Rs 190, when quantity demanded increases from 5000 units to 5200 units, and if point elasticity of demand is -0.8 find P
1
?
- ARs. 220
- BRs. 240
- CRs. 200
- DRs. 250
Solution & Step-by-step Explanation
Using the mid-point / linear definition often applied in such examinations for price elasticity of demand (E
d
):
E
d
=
ΔP
ΔQ
×
Q
1
P
1
Given:
Initial Quantity, Q
1
=5000
Final Quantity, Q
2
=5200
ΔQ=5200−5000=200
Initial Price = P
1
Final Price, P
2
=190
ΔP=190−P
1
Elasticity, E
d
=−0.8
Substitute these values into the formula:
−0.8=
190−P
1
200
×
5000
P
1
−0.8=
5000
200
×
190−P
1
P
1
−0.8=
25
1
×
190−P
1
P
1
−0.8×25=
190−P
1
P
1
−20=
190−P
1
P
1
Cross-multiplying gives:
−20×(190−P
1
)=P
1
−3800+20P
1
=P
1
20P
1
−P
1
=3800
19P
1
=3800
P
1
=
19
3800
=200
Thus, the original price P
1
is Rs. 200.
d
):
E
d
=
ΔP
ΔQ
×
Q
1
P
1
Given:
Initial Quantity, Q
1
=5000
Final Quantity, Q
2
=5200
ΔQ=5200−5000=200
Initial Price = P
1
Final Price, P
2
=190
ΔP=190−P
1
Elasticity, E
d
=−0.8
Substitute these values into the formula:
−0.8=
190−P
1
200
×
5000
P
1
−0.8=
5000
200
×
190−P
1
P
1
−0.8=
25
1
×
190−P
1
P
1
−0.8×25=
190−P
1
P
1
−20=
190−P
1
P
1
Cross-multiplying gives:
−20×(190−P
1
)=P
1
−3800+20P
1
=P
1
20P
1
−P
1
=3800
19P
1
=3800
P
1
=
19
3800
=200
Thus, the original price P
1
is Rs. 200.