If radius of _13^27Al nucleus is estimated to be 3.6 Fermi then the radius _52^125Te nucleus be nearly: - Physics MCQ AIEEE 2026 | ExamTest.live

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If radius of_{13}^{27} Al nucleus is estimated to be 3.6 Fermi then the radius_{52}^{125} Te nucleus be nearly:

Solution & Step-by-step Explanation

Nuclear radius R \propto A^{1/3} where A is the mass number. \frac{R _{T e}}{R _{A l}} = (\frac{A _{T e}}{A _{A l}})^{1/3} \frac{R _{T e}}{3.6} = (\frac{125}{27})^{1/3} = \frac{5}{3} R_{T e} = 3.6 \times \frac{5}{3} = 1.2 \times 5 = 6.0 Fermi

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If radius of_{13}^{27} Al nucleus is estimated to be 3.6 Fermi then the radius_{52}^{125} Te nucleus be nearly:

6 fermi

8 fermi

4 fermi

5 fermi

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