If Ram walks at the speed of 3 km/hr , then he reaches his school 6 minutes late, but if he walks at the speed of 4 km/hr , then he reaches 4 minutes - Quantitative Aptitude MCQ SSC CGL 2026 | ExamTest.live

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If Ram walks at the speed of 3 km/hr, then he reaches his school 6 minutes late, but if he walks at the speed of 4 km/hr, then he reaches 4 minutes before the scheduled time. What is the distance (in cm) of his school from his house?

Solution & Step-by-step Explanation

Let the distance to the school be D km .The time difference between arriving 6 minutes late and 4 minutes early is: Δ t = 6 - (- 4) = 10 minutes = \frac{10}{60} hours = \frac{1}{6} hours Using the time formula Time = \frac{Distance}{Speed} : \frac{D}{3} - \frac{D}{4} = \frac{1}{6} Taking the LCM on the left side: \frac{4 D - 3 D}{12} = \frac{1}{6} \frac{D}{12} = \frac{1}{6} D = \frac{12}{6} = 2 km

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If Ram walks at the speed of 3 km/hr, then he reaches his school 6 minutes late, but if he walks at the speed of 4 km/hr, then he reaches 4 minutes before the scheduled time. What is the distance (in cm) of his school from his house?

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