If A + A = x , then find the value of x . - Quantitative Aptitude MCQ SSC CGL 2026 | ExamTest.live

mediumMCQSSC CGL2026Quantitative Aptitude

1 mark

If sec A + tan A = x, then find the value of x .

Solution & Step-by-step Explanation

Expressing sec A and tan A in terms of sin A and cos A : x = sec A + tan A = \frac{1}{cos A} + \frac{sin A}{cos A} = \frac{1 + sin A}{cos A} Now, let's look at Option D: \frac{1 + sin A}{1 - sin A} = \frac{( 1 + sin A ) ( 1 + sin A )}{( 1 - sin A ) ( 1 + sin A )} = \frac{( 1 + sin A ) ^{2}}{1 - sin ^{2} A} Since 1 - sin^{2} A = cos^{2} A : \frac{( 1 + sin A ) ^{2}}{cos ^{2} A} = \frac{1 + sin A}{cos A} Thus, x = \frac{1 + s i n A}{1 - s i n A} .

Try it yourself before checking the explanation above.

If sec A + tan A = x, then find the value of x .

\frac{1 - s i n A}{1 + s i n A}

\frac{1 + s i n A}{1 - s i n A}

\frac{1 - s i n A}{1 + s i n A}

\frac{1 + s i n A}{1 - s i n A}

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