If p_0q_0 = 160 , p_0q_1 = 250 , p_1q_0 = 200 and p_1q_1 = 288 , then Fisher's ideal index number is: - Mathematics MCQ Mathematics Mock Test - 4 2026 | ExamTest.live

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If \sum p_{0} q_{0} = 160, \sum p_{0} q_{1} = 250, \sum p_{1} q_{0} = 200 and \sum p_{1} q_{1} = 288, then Fisher's ideal index number is:

Solution & Step-by-step Explanation

Fisher's Ideal Index Number (F) is the geometric mean of Laspeyres' (L) and Paasche's (P) indices: F = L \times P \times 100 L = \frac{\sum p _{1} q _{0}}{\sum p _{0} q _{0}} = \frac{200}{160} = 1.25 P = \frac{\sum p _{1} q _{1}}{\sum p _{0} q _{1}} = \frac{288}{250} = 1.152 F = 1.25 \times 1.152 \times 100 = 1.44 \times 100 = 1.2 \times 100 = 120

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If \sum p_{0} q_{0} = 160, \sum p_{0} q_{1} = 250, \sum p_{1} q_{0} = 200 and \sum p_{1} q_{1} = 288, then Fisher's ideal index number is:

125

115.2

119.02

120

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