If the 10-digit number 96530y15x8 is divisible by 72, then what is the value of (3x−7y) for the maximum value of x?
- A3
- B5
- C8
- D4
Solution & Step-by-step Explanation
A number is divisible by 72 if it is divisible by both 8 and 9.
1. Divisibility by 8:
The last three digits 5x8 must be divisible by 8.
Let's check values of x from 9 downwards to maximize x:
If x=9: 598÷8=74.75 (No)
If x=8: 588÷8=73.5 (No)
If x=7: 578÷8=72.25 (No)
If x=6: 568÷8=71 (Yes)
Thus, the maximum value of x=6.
2. Divisibility by 9:
The sum of all digits must be divisible by 9.
Sum=9+6+5+3+0+y+1+5+x+8
Sum=37+x+y
Substitute x=6:
Sum=37+6+y=43+y
For 43+y to be divisible by 9, y must be 2 (since 45 is divisible by 9).
So, y=2.
3. Evaluate (3x−7y):
3x−7y=3(6)−7(2)=18−14=4
1. Divisibility by 8:
The last three digits 5x8 must be divisible by 8.
Let's check values of x from 9 downwards to maximize x:
If x=9: 598÷8=74.75 (No)
If x=8: 588÷8=73.5 (No)
If x=7: 578÷8=72.25 (No)
If x=6: 568÷8=71 (Yes)
Thus, the maximum value of x=6.
2. Divisibility by 9:
The sum of all digits must be divisible by 9.
Sum=9+6+5+3+0+y+1+5+x+8
Sum=37+x+y
Substitute x=6:
Sum=37+6+y=43+y
For 43+y to be divisible by 9, y must be 2 (since 45 is divisible by 9).
So, y=2.
3. Evaluate (3x−7y):
3x−7y=3(6)−7(2)=18−14=4