If the angles of a triangle are in the ratio of 9:11:16, then the difference between the greatest angle and the smallest angle is:
- A30
∘ - B25
∘ - C40
∘ - D35
∘
Solution & Step-by-step Explanation
Let the angles of the triangle be 9k, 11k, and 16k.
According to the angle sum property of a triangle, the sum of all internal angles is 180
∘
:
9k+11k+16k=180
∘
36k=180
∘
⟹k=
36
180
∘
=5
∘
The greatest angle is 16k and the smallest angle is 9k.
The difference between the greatest and smallest angle is:
Difference=16k−9k=7k
Difference=7×5
∘
=35
∘
According to the angle sum property of a triangle, the sum of all internal angles is 180
∘
:
9k+11k+16k=180
∘
36k=180
∘
⟹k=
36
180
∘
=5
∘
The greatest angle is 16k and the smallest angle is 9k.
The difference between the greatest and smallest angle is:
Difference=16k−9k=7k
Difference=7×5
∘
=35
∘