If the average of six consecutive odd natural numbers is 24, then what is the average of the four smaller numbers out of the six numbers?

Let the six consecutive odd natural numbers be x−5,x−3,x−1,x+1,x+3,x+5.
The average of these six numbers is the middle term, which is the average of x−1 and x+1, equal to x.
Given that the average is 24:

x=24
The six consecutive odd numbers are:

24−5,24−3,24−1,24+1,24+3,24+5⟹19,21,23,25,27,29
The four smaller numbers out of these six are: 19,21,23,25.

The average of these four numbers is:

Average=
4
19+21+23+25
​
=
4
88
​
=22