If the binding energy of the electron in a hydrogen atom is 13.6 eV , the energy required to remove the electron from the first excited state of Li^++ - Physics MCQ AIEEE 2003 2026 | ExamTest.live

hardMCQAIEEE 20032026Physics

1 mark

If the binding energy of the electron in a hydrogen atom is 13.6 eV, the energy required to remove the electron from the first excited state of Li^{++} is:

Solution & Step-by-step Explanation

Energy in Bohr's model: E_{n} = - 13.6 \frac{Z ^{2}}{n ^{2}} eV .For Li^{++}, Z = 3 .First excited state means n = 2 . E_{2} = - 13.6 \times \frac{3 ^{2}}{2 ^{2}} = - 13.6 \times \frac{9}{4} = - 3.4 \times 9 = - 30.6 eV The energy required to remove the electron (ionization) is ∣ E_{2} ∣ = 30.6 eV .

Try it yourself before checking the explanation above.

If the binding energy of the electron in a hydrogen atom is 13.6 eV, the energy required to remove the electron from the first excited state of Li^{++} is:

30.6 eV

13.6 eV

3.4 eV

122.4 eV

Practice with timed mock tests and track your performance across Physics.