If the five-digit number 602xy is divisible by 7 and 33, then the value of (8x−3y) is:

Since the number 602xy is divisible by 33, it must be divisible by both 3 and 11.
The number is also divisible by 7. Therefore, it must be divisible by the least common multiple (LCM) of 7 and 33.

LCM(7,33)=7×33=231
Let the maximum possible value of the five-digit number be 60299. Let's divide 60299 by 231:

60299÷231=261.034
Let's find the exact multiple of 231:

231×261=60291
Let's check if the digits match the format 602xy:
For 60291, the last two digits are x=9 and y=1.

Let's check the divisibility constraints to ensure uniqueness:
If we try the next lower multiple, 231×260=60060, which does not match the prefix 602.
If we try 231×262=60522, which does not match either.
Thus, 60291 is the unique number matching the form.

So, x=9 and y=1.

Now, let's find the value of (8x−3y):

8x−3y=8(9)−3(1)=72−3=69