If the letters of the word "EVEREST" are arranged alphabetically, then which letter would be $2^{\text{nd}}$ to the right from the second letter of the word?

Let's follow the steps to arrange and find the letter:
1. The original word is: $\text{E, V, E, R, E, S, T}$
2. Count of letters: $\text{E}=3$, $\text{R}=1$, $\text{S}=1$, $\text{T}=1$, $\text{V}=1$
3. Arranging them in alphabetical order gives: $\text{E, E, E, R, S, T, V}$
4. The second letter from the left in this arranged sequence is $\text{E}$ (at index 2).
5. Moving $2^{\text{nd}}$ to the right from this letter $\text{E}$ leads to the $4^{\text{th}}$ letter in the sequence, which is $\text{R}$.