If the measure of the interior angle of a regular polygon is 108
∘
greater than the measure of its exterior angle then how many sides does it have?
- A10
- B12
- C15
- D18
Solution & Step-by-step Explanation
Let the measure of the exterior angle be x
∘
.
Then, the measure of the interior angle is (x+108)
∘
.
We know that the sum of an interior angle and an exterior angle of a regular polygon is always 180
∘
:
Interior Angle+Exterior Angle=180
∘
(x+108)+x=180
2x+108=180
2x=72⟹x=36
∘
The exterior angle of the polygon is 36
∘
.
The formula for the number of sides (n) of a regular polygon is:
n=
Exterior Angle
360
∘
n=
36
∘
360
∘
=10
So, the polygon has 10 sides.
∘
.
Then, the measure of the interior angle is (x+108)
∘
.
We know that the sum of an interior angle and an exterior angle of a regular polygon is always 180
∘
:
Interior Angle+Exterior Angle=180
∘
(x+108)+x=180
2x+108=180
2x=72⟹x=36
∘
The exterior angle of the polygon is 36
∘
.
The formula for the number of sides (n) of a regular polygon is:
n=
Exterior Angle
360
∘
n=
36
∘
360
∘
=10
So, the polygon has 10 sides.