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If the measure of the interior angle of a regular polygon is 108

greater than the measure of its exterior angle then how many sides does it have?

  1. A
    10
  2. B
    12
  3. C
    15
  4. D
    18

Solution & Step-by-step Explanation

Let the measure of the exterior angle be x

.
Then, the measure of the interior angle is (x+108)

.

We know that the sum of an interior angle and an exterior angle of a regular polygon is always 180

:

Interior Angle+Exterior Angle=180


(x+108)+x=180
2x+108=180
2x=72⟹x=36


The exterior angle of the polygon is 36

.

The formula for the number of sides (n) of a regular polygon is:

n=
Exterior Angle
360




n=
36


360



=10
So, the polygon has 10 sides.

Practice this question

Try it yourself before checking the explanation above.

If the measure of the interior angle of a regular polygon is 108

greater than the measure of its exterior angle then how many sides does it have?
A
10
B
12
C
15
D
18

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