If the momentum of a body increases from $10$ units to $25$ units in $5\text{sec}$, then the force acting on it is

According to Newton's Second Law of Motion, the force ($F$) acting on an object is equal to the rate of change of its momentum ($\Delta p$) with respect to time ($t$).
$$\text{Force }(F)=\frac{\text{Change in momentum }(\Delta p)}{\text{Time taken }(t)}$$
Given data:Initial momentum ($p_1$) = $10$ unitsFinal momentum ($p_2$) = $25$ unitsTime interval ($t$) = $5\text{sec}$ Calculating change in momentum:
$$\Delta p=p_2-p_1=25-10=15\text{ units}$$
Now, computing the force:
$$F=\frac{15}{5}=3\text{ units}$$