If the operations are defined as follows:
* $A\ast B$ means $A+B\times 4$
* $A\#B$ means $A-B÷3$
* A \ B$means$ A \times B + 21$Findthevalueof$ (35 \# (16 * 20)) \$5$.

Let's solve the expression (35 \# (16 * 20)) \ 5$stepbystepusingBODMAS/rulesspecified:1.\ast \ast First,evaluatetheinnermostbracket$ (16 * 20)$:\ast \ast Accordingtodefinition,$ A * B = A + B \times 4$.$$16\ast 20=16+20\times 4=16+80=96$$2.\ast \ast Next,evaluatetheouterbracket$ (35 \# 96)$:\ast \ast Accordingtodefinition,$ A \# B = A - B \div 3$.$$35\#96=35-\frac{96}{3}=35-32=3$$3.\ast \ast Finally,evaluatethefullexpression$ 3 \$5$:**
According to definition, A \ B = A \times B + 21$.$3 \ 5 = 3 \times 5 + 21 = 15 + 21 = 36
$$Thevalueis$ 36$.