If the ratio of three numbers A, B and C is 2:3:5, and the sum of the squares of these numbers is 3800, then the value of C is:
- A30
- B40
- C50
- D20
Solution & Step-by-step Explanation
Let the three numbers be A=2x, B=3x, and C=5x.
According to the problem, the sum of their squares is 3800:
(2x)
2
+(3x)
2
+(5x)
2
=3800
4x
2
+9x
2
+25x
2
=3800
38x
2
=3800
x
2
=100⟹x=10
Now, find the value of C:
C=5x=5×10=50
According to the problem, the sum of their squares is 3800:
(2x)
2
+(3x)
2
+(5x)
2
=3800
4x
2
+9x
2
+25x
2
=3800
38x
2
=3800
x
2
=100⟹x=10
Now, find the value of C:
C=5x=5×10=50