If the semi-perimeter and area of a rectangular field whose length and breadth are 'x' and 'y' is 12cm and 28cm
2
, respectively, then find the value of x
4
+x
2
y
2
+y
4
.
- A6690
- B6960
- C6609
- D6906
Solution & Step-by-step Explanation
Given parameters:
Length = x, Breadth = y
Semi-perimeter =x+y=12
Area =xy=28
We need to evaluate the expression: x
4
+x
2
y
2
+y
4
.
We can factorize or rewrite this expression using algebraic identities:
x
4
+x
2
y
2
+y
4
=(x
2
+y
2
)
2
−x
2
y
2
First, let's find (x
2
+y
2
):
x
2
+y
2
=(x+y)
2
−2xy
Substitute the given values:
x
2
+y
2
=(12)
2
−2(28)
x
2
+y
2
=144−56=88
Now, substitute this back into the rewritten target expression:
x
4
+x
2
y
2
+y
4
=(x
2
+y
2
)
2
−(xy)
2
=(88)
2
−(28)
2
Using the identity a
2
−b
2
=(a−b)(a+b):
=(88−28)(88+28)
=(60)×(116)
=6960
Length = x, Breadth = y
Semi-perimeter =x+y=12
Area =xy=28
We need to evaluate the expression: x
4
+x
2
y
2
+y
4
.
We can factorize or rewrite this expression using algebraic identities:
x
4
+x
2
y
2
+y
4
=(x
2
+y
2
)
2
−x
2
y
2
First, let's find (x
2
+y
2
):
x
2
+y
2
=(x+y)
2
−2xy
Substitute the given values:
x
2
+y
2
=(12)
2
−2(28)
x
2
+y
2
=144−56=88
Now, substitute this back into the rewritten target expression:
x
4
+x
2
y
2
+y
4
=(x
2
+y
2
)
2
−(xy)
2
=(88)
2
−(28)
2
Using the identity a
2
−b
2
=(a−b)(a+b):
=(88−28)(88+28)
=(60)×(116)
=6960