If the slope of the tangent to curve $y=x^3$ at a point is equal to the ordinate of the point, then the point is:

Curve: $y=x^3$.Slope of tangent $\frac{dy}{dx}=3x^2$.According to the problem, slope = ordinate ($y$).$3x^2=y$ Substitute $y=x^3$:$3x^2=x^3⟹x^3-3x^2=0⟹x^2(x-3)=0$.So $x=0$ or $x=3$.If $x=0,y=0^3=0$. Point is $(0,0)$.If $x=3,y=3^3=27$. Point is $(3,27)$.Checking options, $(3,27)$ is present.