If the speed of a boat moving against the current is 18 km/hr , what is the speed of the stream if the boat's speed downstream is 50\% greater than it - Quantitative Aptitude MCQ D.ZU-24 2026 | ExamTest.live

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If the speed of a boat moving against the current is 18 km/hr, what is the speed of the stream if the boat's speed downstream is 50% greater than its speed upstream?

Solution & Step-by-step Explanation

Given parameters: * Upstream speed (v_{u}) = 18 km/hr Downstream speed (v_{d}) is 50% greater than upstream speed: v_{d} = v_{u} + 50% of v_{u} v_{d} = 18 + (\frac{50}{100} \times 18) = 18 + 9 = 27 km/hr The formula for the speed of the stream (v_{s}) is: v_{s} = \frac{v _{d} - v _{u}}{2} v_{s} = \frac{27 - 18}{2} = \frac{9}{2} = 4.5 km/hr

Try it yourself before checking the explanation above.

If the speed of a boat moving against the current is 18 km/hr, what is the speed of the stream if the boat's speed downstream is 50% greater than its speed upstream?

4.8 km/hr

4.6 km/hr

5.2 km/hr

4.5 km/hr

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