If there are 999 bases in an RNA that code for a protein with 333 amino acids, and the base at position 901 is deleted such that the length of the RNA becomes 998 bases, how many codons will be altered?
- A1
- B11
- C33
- D333
Solution & Step-by-step Explanation
A codon consists of 3 bases.
Bases from 1 to 900 (covering 300 codons) remain unchanged.
The deletion occurs at base 901. This causes a frameshift mutation for all subsequent bases.
Total bases after deletion in the affected region =999−900=99 (originally).
Number of codons from base 901 to 999 is
3
99
=33.
All these 33 codons will be altered.
Bases from 1 to 900 (covering 300 codons) remain unchanged.
The deletion occurs at base 901. This causes a frameshift mutation for all subsequent bases.
Total bases after deletion in the affected region =999−900=99 (originally).
Number of codons from base 901 to 999 is
3
99
=33.
All these 33 codons will be altered.