If there are $999$ bases in an RNA that codes for a protein with $333$ amino acids, and the base at position $901$ is deleted such that the length of the RNA becomes $998$ bases, how many codons will be altered?

A codon consists of $3$ bases.The deletion occurs at position $901$.The bases from $1$ to $900$ remain unchanged.The number of unchanged codons $=\frac{900}{3}=300$.The total original codons were $333$.The number of codons altered $=333-300=33$.Deletion at any point in a codon shifts the reading frame for all subsequent codons (Frame shift mutation).