If $x>y=x^3+y^3$ and $x\text{@}y=x^3-y^3$, then find the value of $3>(2\text{@}1)$.

Given two custom operators:
1. $x>y=x^3+y^3$
2. $x\text{@}y=x^3-y^3$

We need to evaluate the expression $3>(2\text{@}1)$.

**Step 1: Solve inside the bracket first $(2\text{@}1)$ **
Using the rule for '@':

$$2\text{@}1=2^3-1^3=8-1=7$$

Step 2: Substitute this value back into the main expression
Now evaluate $3>7$:
Using the rule for '>':

$$3>7=3^3+7^3$$

$$3>7=27+343=370$$

Thus, the final value is $370$.