If x=3−4y, then (x
3
+64y
3
+36xy) is equal to:
- A27(1 + 3xy)
- B9(3 + 5xy)
- C27(1 + xy)
- D27
Solution & Step-by-step Explanation
Given:
x=3−4y⟹x+4y=3
We need to evaluate the expression x
3
+64y
3
+36xy.
We know the identity:
(a+b)
3
=a
3
+b
3
+3ab(a+b)
Let a=x and b=4y.
(x+4y)
3
=x
3
+(4y)
3
+3(x)(4y)(x+4y)
(x+4y)
3
=x
3
+64y
3
+12xy(x+4y)
Substitute x+4y=3 into the identity:
(3)
3
=x
3
+64y
3
+12xy(3)
27=x
3
+64y
3
+36xy
Therefore, the value of the given expression is 27.
x=3−4y⟹x+4y=3
We need to evaluate the expression x
3
+64y
3
+36xy.
We know the identity:
(a+b)
3
=a
3
+b
3
+3ab(a+b)
Let a=x and b=4y.
(x+4y)
3
=x
3
+(4y)
3
+3(x)(4y)(x+4y)
(x+4y)
3
=x
3
+64y
3
+12xy(x+4y)
Substitute x+4y=3 into the identity:
(3)
3
=x
3
+64y
3
+12xy(3)
27=x
3
+64y
3
+36xy
Therefore, the value of the given expression is 27.