If $xy=-30$ and $x^2+y^2=61$, then find the value of $(x+y)$.

Using the algebraic identity:
$$(x+y{)}^2=x^2+y^2+2xy$$
Substitute the given values into the identity:
$$(x+y{)}^2=61+2(-30)$$
$$(x+y{)}^2=61-60=1$$
Taking the positive square root as per options provided:
$$x+y=1$$