![image](https://pub-7faa453bd1ec4bf0a04cc031c6f058de.r2.dev/images/c7b48b2c-8bf5-407e-9933-08c30c3b849c.png)

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![image](https://pub-7faa453bd1ec4bf0a04cc031c6f058de.r2.dev/images/c7b48b2c-8bf5-407e-9933-08c30c3b849c.png) Electrons accelerated by potential V are diffracted from a crystal. If d = 1 Å and i = 30^ , V should be about ( h = 6.6 × 10^-34 J s, m_e = 9.1 × 10^-31 kg, e = 1.6 × 10^-19 C ):

Accepted Answer

![image](https://pub-7faa453bd1ec4bf0a04cc031c6f058de.r2.dev/images/e28c9ab7-52bc-4be5-a78b-962a7ecfe42c.png) For diffraction, the condition is 2d i = nλ .Assuming first order diffraction ( n=1 ): λ = 2d 30^= 2(1 Å) × √(3)2 = √(3) Å = 1.732 × 10^-10 m De Broglie wavelength is λ = h/√(2meV) . V = h^2/2meλ^2 = (6.6 × 10^-34)^22 × 9.1 × 10^-31 × 1.6 × 10^-19 × (1.732 × 10^-10)^2 V ≈ 50 V .

Electrons accelerated by potential $V$ are diffracted from a crystal. If $d = 1 \overset{˚}{A}$ and $i = 3 0^{\circ}$ , $V$ should be about ( $h = 6.6 \times 1 0^{- 34} J s, m_{e} = 9.1 \times 1 0^{- 31} kg, e = 1.6 \times 1 0^{- 19} C$ ):

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Electrons accelerated by potential V are diffracted from a crystal. If d=1A˚ and i=30∘, V should be about (h=6.6×10−34J s,me​=9.1×10−31kg,e=1.6×10−19C):