Select a figure from the given options which will continue the same series as established by the four problem figures.

Let's track the movement of both elements (the white circle and the white hexagon) inside the blue square from one frame to the next:
1. Movement of the Circle:
* Frame 1 to Frame 2: Moves from the bottom-right corner to the top-left corner (shifts counter-clockwise along the corners by 2 places).
* Frame 2 to Frame 3: Moves from the top-left corner to the top-right corner (shifts counter-clockwise along the corners by 1 place).
* Frame 3 to Frame 4: Moves from the top-right corner to the bottom-right corner (shifts counter-clockwise along the corners by 1 place).
* Following this alternating pattern (+2, +1, +1 corners counter-clockwise isn't perfectly uniform, so let's re-verify the collective relative positions):
Alternatively, notice that the entire inner layout rotates *$90^{\circ }$ counter-clockwise** at each step:
* In Frame 1: Hexagon is at bottom-left, Circle is at bottom-right.
* Rotating this entire square $90^{\circ }$ counter-clockwise puts Hexagon at bottom-right and Circle at top-right. But Frame 2 shows Hexagon at bottom-left, Circle at top-left. Let's look at independent tracks or a strict corner rotation:
* Let's look at the options relative to Frame 4:
* Frame 1: Hexagon (Bottom-Left), Circle (Bottom-Right)
* Frame 2: Hexagon (Bottom-Left), Circle (Top-Left)
* Frame 3: Hexagon (Top-Left), Circle (Top-Right)
* Frame 4: Hexagon (Top-Right), Circle (Bottom-Right)
* Notice the Hexagon positions: Bottom-Left $\to$ Bottom-Left $\to$ Top-Left $\to$ Top-Right. It moves $0\to 1\to 1$ step clockwise.
* Let's observe the complete shape rotation: If we rotate Frame 1 by $90^{\circ }$ clockwise, the bottom-left hexagon goes to top-left, and bottom-right circle goes to bottom-left. This doesn't match Frame 2.
* Let's look at the absolute step-by-step transformation:
* Hexagon: Frame 1 (Bottom-Left) $\to$ Frame 2 (Bottom-Left) $\to$ Frame 3 (Top-Left) $\to$ Frame 4 (Top-Right). It stays in place once, then moves $90^{\circ }$ clockwise, then moves $90^{\circ }$ clockwise. Therefore, in the next step, it should either stay in place at (Top-Right) or move $90^{\circ }$ clockwise to (Bottom-Right).
* Circle: Frame 1 (Bottom-Right) $\to$ Frame 2 (Top-Left) $\to$ Frame 3 (Top-Right) $\to$ Frame 4 (Bottom-Right).
* From Frame 1 to 2, it moves diagonally opposite.
* From Frame 2 to 3, it moves $90^{\circ }$ clockwise.
* From Frame 3 to 4, it moves $90^{\circ }$ clockwise.
* Therefore, from Frame 4 to 5, it should move either diagonally opposite (to Top-Left) or continue $90^{\circ }$ clockwise to (Bottom-Left).

* Let's test the uniform step logic:
* Frame 1 to Frame 2: Hexagon stays, Circle moves 2 corners clockwise/diagonally.
* Frame 2 to Frame 3: Both elements shift $90^{\circ }$ clockwise.
* Frame 3 to Frame 4: Both elements shift $90^{\circ }$ clockwise.
* If the shift sequence follows: [Change pattern from 1$\to$ 2, then stable rotation for 2$\to$ 3 and 3$\to$ 4], the next logical transformation from 4$\to$ 5 should continue the $90^{\circ }$ clockwise rotation for both items:
* Hexagon at Top-Right $\to$ moves $90^{\circ }$ clockwise to Bottom-Right.
* Circle at Bottom-Right $\to$ moves $90^{\circ }$ clockwise to Bottom-Left.

* This matches Figure B, where the hexagon is at the bottom-left and the circle is at the bottom-right? Wait, let's look at Figure B: Hexagon is at bottom-left, Circle is at bottom-right. That is identical to Frame 1! This means the series completes a full cycle and repeats Frame 1.
* Let's check if Frame 1 to 4 represents a periodic sequence:
* Frame 1: Hexagon (BL), Circle (BR)
* Frame 4: Hexagon (TR), Circle (BR)
* If the entire figure rotates $90^{\circ }$ counter-clockwise:
* Frame 1 rotated $90^{\circ }$ CCW $\to$ Hexagon (BR), Circle (TR). This is the exact mirror/inverse of Frame 2.

* Let's look at the choices:
* A has Circle (TL), Hexagon (BL) — identical to Frame 2.
* B has Hexagon (BL), Circle (BR) — identical to Frame 1.
* C has Hexagon (TR), Circle (BR) — identical to Frame 4.
* D has Hexagon (TL), Circle (TR) — identical to Frame 3.

* Since the options are exactly the four frames, this is a clear 4-step cyclic series. Frame 1, Frame 2, Frame 3, Frame 4... the 5th frame must be identical to Frame 1.
* Frame 1 has the hexagon at the bottom-left and the circle at the bottom-right, which is exactly Figure B.