![image](https://pub-7faa453bd1ec4bf0a04cc031c6f058de.r2.dev/images/a5937446-6610-4d8c-9ebb-4b2ceae40ef4.png) A p-v diagram represents the thermodynam - Physics MCQ JEE Main 2026 | ExamTest.live

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A p - v diagram represents the thermodynamic cycle of an engine, operating with an ideal monoatomic gas. The cycle is a rectangle with vertices (v_{0}, p_{0}), (2 v_{0}, p_{0}), (2 v_{0}, 2 p_{0}), (v_{0}, 2 p_{0}) . The amount of heat extracted from the source in a single cycle is:

Solution & Step-by-step Explanation

Heat is absorbed from the source in processes where temperature increases.Let A (v_{0}, p_{0}), B (2 v_{0}, p_{0}), C (2 v_{0}, 2 p_{0}), D (v_{0}, 2 p_{0}) .Process A \to B : Isobaric expansion. Δ Q_{1} = n C_{p} Δ T = \frac{5}{2} p_{0} Δ v = \frac{5}{2} p_{0} (v_{0}) = 2.5 p_{0} v_{0} .Process B \to C : Isochoric heating. Δ Q_{2} = n C_{v} Δ T = \frac{3}{2} v Δ p = \frac{3}{2} (2 v_{0}) (p_{0}) = 3 p_{0} v_{0} .Total heat absorbed from source = 2.5 p_{0} v_{0} + 3 p_{0} v_{0} = 5.5 p_{0} v_{0} = \frac{11}{2} p_{0} v_{0} .

Try it yourself before checking the explanation above.

A p - v diagram represents the thermodynamic cycle of an engine, operating with an ideal monoatomic gas. The cycle is a rectangle with vertices (v_{0}, p_{0}), (2 v_{0}, p_{0}), (2 v_{0}, 2 p_{0}), (v_{0}, 2 p_{0}) . The amount of heat extracted from the source in a single cycle is:

\frac{13}{2} p_0v_0

\frac{11}{2} p_0v_0

4 p_0v_0

p_0v_0

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