In a 200-m race, if A gives B a head start of 35m, then A wins the race by 20sec. Alternatively, if A gives B a head start of 55m, the race ends in a dead heat. How long does A take to run 200m?
- A165 sec
- B145 sec
- C150 sec
- D155 sec
Solution & Step-by-step Explanation
Let the speed of A be v
A
and the speed of B be v
B
.
Let the time taken by A to cover 200m be t
A
.
Case 2: A gives B a head start of 55m and the race ends in a dead heat.
This means that in the time t
A
that A takes to cover 200m, B covers (200−55)=145m.
Therefore, the time taken by B to run 145m is t
A
.
Speed of B (v
B
)=
t
A
145
Case 1: A gives B a head start of 35m, and A wins by 20sec.
This means B runs (200−35)=165m, and takes 20sec more than A's total time.
Time taken by B to cover 165m=t
A
+20
v
B
165
=t
A
+20
Substitute the value of v
B
from Case 2 into this equation:
(
t
A
145
)
165
=t
A
+20
145
165
t
A
=t
A
+20
29
33
t
A
−t
A
=20
29
4
t
A
=20
t
A
=
4
20×29
=5×29=145sec
Thus, A takes 145sec to run 200m.
A
and the speed of B be v
B
.
Let the time taken by A to cover 200m be t
A
.
Case 2: A gives B a head start of 55m and the race ends in a dead heat.
This means that in the time t
A
that A takes to cover 200m, B covers (200−55)=145m.
Therefore, the time taken by B to run 145m is t
A
.
Speed of B (v
B
)=
t
A
145
Case 1: A gives B a head start of 35m, and A wins by 20sec.
This means B runs (200−35)=165m, and takes 20sec more than A's total time.
Time taken by B to cover 165m=t
A
+20
v
B
165
=t
A
+20
Substitute the value of v
B
from Case 2 into this equation:
(
t
A
145
)
165
=t
A
+20
145
165
t
A
=t
A
+20
29
33
t
A
−t
A
=20
29
4
t
A
=20
t
A
=
4
20×29
=5×29=145sec
Thus, A takes 145sec to run 200m.