In a certain code language, 'BHOPAL' is written as 'OBHLPA', and 'KANPUR' is written as 'NKARPU'. How will 'INDORE' be written in that language?
- ADINEOR
- BERINDO
- CDNIORE
- DNIDROE
Solution & Step-by-step Explanation
Let's analyze the scrambling pattern by grouping letters into pairs:
In 'BHOPAL':
Scribd
Pair 1: B, H → Reversed to H, B
Pair 2: O, P → Reversed to P, O
Pair 3: A, L → Reversed to L, A
Wait, looking at the code 'OBHLPA':
Positions 123456 of BHOPAL become 321564? Let's check:
B(1) H(2) O(3) P(4) A(5) L(6) → O(3) B(1) H(2) L(6) P(4) A(5) - No.
Let's look closer:
BHOPAL divided into two halves: BHO and PAL.
BHO rearranged to OBH (shifting right/rotating).
PAL rearranged to LPA.
Let's check KANPUR:
KAN → NKA
PUR → RPU
This means for each 3-letter block, the last letter moves to the front:
1 2 3→3 1 2
Applying this to INDORE:
First block: IND → DIN
Second block: ORE → EOR
Thus, INDORE is written as DINEOR.
In 'BHOPAL':
Scribd
Pair 1: B, H → Reversed to H, B
Pair 2: O, P → Reversed to P, O
Pair 3: A, L → Reversed to L, A
Wait, looking at the code 'OBHLPA':
Positions 123456 of BHOPAL become 321564? Let's check:
B(1) H(2) O(3) P(4) A(5) L(6) → O(3) B(1) H(2) L(6) P(4) A(5) - No.
Let's look closer:
BHOPAL divided into two halves: BHO and PAL.
BHO rearranged to OBH (shifting right/rotating).
PAL rearranged to LPA.
Let's check KANPUR:
KAN → NKA
PUR → RPU
This means for each 3-letter block, the last letter moves to the front:
1 2 3→3 1 2
Applying this to INDORE:
First block: IND → DIN
Second block: ORE → EOR
Thus, INDORE is written as DINEOR.