In a certain code language, 'BLASPHEMY' is written as 'ZNFIQTBMC'. How will 'ENGROSSED' be written in that language?
- AEFTTPSHOF
- BFETTRSFPF
- CFETTSPHOF
- DEFTUPSHPF
Solution & Step-by-step Explanation
Let's analyze the pattern for 'BLASPHEMY' → 'ZNFIQTBMC'.
Split the 9-letter word into three equal parts of 3 letters each: BLA, SPH, EMY.
First 3 letters (BLA): Reverse them → ALB.
Add +1 to each letter positional value:
A+1=B
L+1=M
B+1=C
Wait, let's look at the result ZNFIQTBMC. The last three letters are BMC. This matches our output! So the first part moves to the end.
Middle 3 letters (SPH): Reverse them → HPS.
Add +1 to each letter positional value:
H+1=I
P+1=Q
S+1=T
This gives IQT, which is the middle section of the code.
Last 3 letters (EMY): Reverse them → YME.
Add +1 to each letter positional value:
Y+1=Z
M+1=N
E+1=F
This gives ZNF, which is the first section of the code.
Summary of pattern: Split into 3 segments of 3 letters each: S
1
,S
2
,S
3
.
The coded sequence layout is: [Reverse(S
3
)+1]+[Reverse(S
2
)+1]+[Reverse(S
1
)+1].
Let's apply this to ENGROSSED:
S
1
=ENG→Reverse=GNE
+1
HOF
S
2
=ROS→Reverse=SOR
+1
TPS
S
3
=SED→Reverse=DES
+1
EFT
Combining the segments in the order of (S
3
→S
2
→S
1
):
EFT+TPS+HOF=EFTTPSHOF
Split the 9-letter word into three equal parts of 3 letters each: BLA, SPH, EMY.
First 3 letters (BLA): Reverse them → ALB.
Add +1 to each letter positional value:
A+1=B
L+1=M
B+1=C
Wait, let's look at the result ZNFIQTBMC. The last three letters are BMC. This matches our output! So the first part moves to the end.
Middle 3 letters (SPH): Reverse them → HPS.
Add +1 to each letter positional value:
H+1=I
P+1=Q
S+1=T
This gives IQT, which is the middle section of the code.
Last 3 letters (EMY): Reverse them → YME.
Add +1 to each letter positional value:
Y+1=Z
M+1=N
E+1=F
This gives ZNF, which is the first section of the code.
Summary of pattern: Split into 3 segments of 3 letters each: S
1
,S
2
,S
3
.
The coded sequence layout is: [Reverse(S
3
)+1]+[Reverse(S
2
)+1]+[Reverse(S
1
)+1].
Let's apply this to ENGROSSED:
S
1
=ENG→Reverse=GNE
+1
HOF
S
2
=ROS→Reverse=SOR
+1
TPS
S
3
=SED→Reverse=DES
+1
EFT
Combining the segments in the order of (S
3
→S
2
→S
1
):
EFT+TPS+HOF=EFTTPSHOF