In a certain code language, 'CUP' is coded as '45' and 'FIT' is coded as '50'. How will 'FUN' be coded in that language?

Let's determine the code values based on the alphabetical positional values of the letters ($A=1,B=2,\dots ,Z=26$).For CUP:$\text{C}=3$$\text{U}=21$$\text{P}=16$$\text{Sum}=3+21+16=40$$\text{Code}=40+5=45$ For FIT:$\text{F}=6$$\text{I}=9$$\text{T}=20$$\text{Sum}=6+9+20=35$$\text{Code}=35+15=50$ (Wait, adding 5 to 40 gives 45, but adding 15 to 35 gives 50. Let's look for an alternative logic).Let's check the sum of opposite positions:$\text{C}\to 24$, $\text{U}\to 6$, $\text{P}\to 11$. $\text{Sum}=24+6+11=41\ne 45$.Let's re-verify the sum of forward positions:For CUP: $3+21+16=40$. Total letters = 3? $40+5=45$.For FIT: $6+9+20=35$. Let's check letter position values carefully: $\text{F}=6,\text{I}=9,\text{T}=20$, sum is 35. To reach 50, we add 15. Why 5 and 15?Let's look at vowels vs consonants: In CUP, the vowel is U (21). In FIT, the vowel is I (9). No immediate relation.Let's test another direct mathematical logic:Could it be $\text{Sum of vowels}\times 2+\text{consonants}$?For CUP: $(3+16)+21\times 2=19+42=61$.Let's try: $\text{Sum}+(\text{Number of vowels}\times \text{something})$ or adding a specific constant:Wait! Let's check positional values again.Is it possible that the code is derived from something else? Let's check:$\text{C}=3,\text{U}=21,\text{P}=16\to \text{Sum}=40$. Number of letters is 3. Maybe add $5\times 1$?For FIT: $\text{F}=6,\text{I}=9,\text{T}=20\to \text{Sum}=35$.Let's check the position values from backwards:$\text{C}=27-3=24$$\text{U}=27-21=6$$\text{P}=27-16=11$$\text{Sum}=24+6+11=41$. Add $4=45$.$\text{F}=27-6=21$$\text{I}=27-9=18$$\text{T}=27-20=7$$\text{Sum}=21+18+7=46$. Add $4=50$.Wow! The logic is: (Sum of reverse alphabetical positions) + 4.Let's apply this logic to FUN:Reverse position of $\text{F}=27-6=21$ Reverse position of $\text{U}=27-21=6$ Reverse position of $\text{N}=27-14=13$$\text{Sum of reverse positions}=21+6+13=40$$\text{Total code}=40+4=44$