In a certain code language, ‘DEVOTION’ is written as ‘EHAVREIF’, and ‘SANSKRIT’ is written as ‘TDSZINCL’. How will ‘LICENSED’ be written in that language?

Let's analyze the pattern by dividing the 8-letter words into two halves of 4 letters each.
Word 1: DEVOTION → EHAVREIF

First Half: DEVO

Reverse the order: O-V-E-D

Apply operation to each letter:

O−10=E

V+12=H

E−4=A

D+18=V

This logic does not align perfectly. Let's look at direct vowel-consonant shifts or alternate patterns.

Alternative Pattern:
Let's check positional operations between DEVOTION and EHAVREIF:

D(+1)→E

E(+3)→H

V(−21)→A (or V(22)→A(1) via opposition)
Let's look at cross pairs or vowel/consonant rules:
Vowels: E, O, I, O
Consonants: D, V, T, N

Let's re-examine carefully:
D (+1) = E
E (+3) = H
V (+5) = A (22 + 5 = 27 → A)
O (+7) = V (15 + 7 = 22 → V)
T (-11) = I? No.

Let's check from the end or split pairs:
The first half: D E V O → E H A V

D+1=E

E+3=H

V+5=A (22+5=27≡1)

O+7=V (15+7=22)
So the first four letters are added with consecutive odd numbers: +1,+3,+5,+7.

The second half: T I O N → R E I F

Let's check the relation between TION and REIF:

T(−2)=R

I(−4)=E

O(−6)=I

N(−8)=F
So the last four letters are subtracted with consecutive even numbers: −2,−4,−6,−8.

Word 2: SANSKRIT → TDSZINCL

First Half (+1, +3, +5, +7):

S+1=T

A+3=D

N+5=S

S+7=Z
Matches "TDSZ"

Second Half (-2, -4, -6, -8):

K−2=I

R−4=N

I−6=C

T−8=L
Matches "INCL"

Applying the pattern to LICENSED:

First Half (L I C E):

L(12)+1=13→M

I(9)+3=12→L

C(3)+5=8→H

E(5)+7=12→L
First half code = MLHL

Second Half (N I S E D is 8 letters total: L-I-C-E-N-S-E-D):
Wait, LICENSED has 8 letters: L I C E and N S E D.

N(14)−2=12→L

S(19)−4=15→O

E(5)−6=−1≡25→Y

D(4)−8=−4≡22→V
Second half code = LOYV

Combining both halves: MLHLLOYV