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hardMCQSSC Selection Post 20212026General Intelligence
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In a certain code language, 'FLOWER' is coded as '166', and 'SHIFT' is coded as '73'. How will 'VOLUME' be coded in that language?

  1. A
    212
  2. B
    222
  3. C
    184
  4. D
    148

Solution & Step-by-step Explanation

Let's find the positional values of the letters in SHIFT:
S = 19, H = 8, I = 9, F = 6, T = 20
Sum of forward positional values =19+8+9+6+20=62.
To get 73: 62+11=73. (11 could be a constant or a specific added value).
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Let's look at FLOWER:
F = 6, L = 12, O = 15, W = 23, E = 5, R = 18
Sum of forward values =6+12+15+23+5+18=79.
But the code is 166. Notice that 79×2=158, and 158+8=166. This pattern isn't matching perfectly.

Let's try opposite (backward) positional values:
For SHIFT:
S = 8, H = 19, I = 18, F = 21, T = 7
Sum of opposite positions =8+19+18+21+7=73.
This matches perfectly!

Let's verify with FLOWER using opposite positions:
F = 21, L = 15, O = 12, W = 4, E = 22, R = 9
Sum of opposite positions =21+15+12+4+22+9=83.
If we double it: 83×2=166.
So the logic is: Sum of opposite letter values × (number of vowels? No, FLOWER has 2 vowels, SHIFT has 1 vowel).
Let's see: For SHIFT, multiplied by 1. For FLOWER, multiplied by 2.
This matches the number of vowels in the words!
CK-12 Foundation

SHIFT has 1 vowel ('I') →73×1=73.

FLOWER has 2 vowels ('O', 'E') →83×2=166.

Now apply this logic to VOLUME:
Opposite letters positional values:
V → 5
O → 12
L → 15
U → 6
M → 14
E → 22

Sum =5+12+15+6+14+22=74.
Number of vowels in VOLUME =3 ('O', 'U', 'E').
Total value =74×3=222.

Practice this question

Try it yourself before checking the explanation above.

In a certain code language, 'FLOWER' is coded as '166', and 'SHIFT' is coded as '73'. How will 'VOLUME' be coded in that language?
A
212
B
222
C
184
D
148

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