In a certain code language, 'HUNTER' is coded as 80 and 'TRIAL' is coded as 55. How will 'BURNT' be coded in the same language?
- A70
- B75
- C65
- D80
Solution & Step-by-step Explanation
Let's calculate the sum of positional values of the letters for each word:
For HUNTER:
H=8
U=21
N=14
T=20
E=5
R=18
Sum=8+21+14+20+5+18=86
The code is given as 80. Notice that 86−6=80 (where 6 is the number of letters in 'HUNTER').
For TRIAL:
T=20
R=18
I=9
A=1
L=12
Sum=20+18+9+1+12=60
The code is given as 55. Notice that 60−5=55 (where 5 is the number of letters in 'TRIAL').
Logic: Code=(Sum of letter positions)−(Total number of letters)
Now applying this to BURNT:
B=2
U=21
R=18
N=14
T=20
Sum=2+21+18+14+20=75
Number of letters in 'BURNT' = 5.
Code=75−5=70
For HUNTER:
H=8
U=21
N=14
T=20
E=5
R=18
Sum=8+21+14+20+5+18=86
The code is given as 80. Notice that 86−6=80 (where 6 is the number of letters in 'HUNTER').
For TRIAL:
T=20
R=18
I=9
A=1
L=12
Sum=20+18+9+1+12=60
The code is given as 55. Notice that 60−5=55 (where 5 is the number of letters in 'TRIAL').
Logic: Code=(Sum of letter positions)−(Total number of letters)
Now applying this to BURNT:
B=2
U=21
R=18
N=14
T=20
Sum=2+21+18+14+20=75
Number of letters in 'BURNT' = 5.
Code=75−5=70