In a certain code language, 'LOST' is coded as ‘32’, 'CRAMP' is coded as ‘50’. How will 'FRY' be coded in that language?

Let's evaluate the sum of positional values of the letters in the English alphabet:LOST:

L = 12, O = 15, S = 19, T = 20

Sum = 12 + 15 + 19 + 20 = 66

L e t^{'} s l oo ka tt h ere v erse p os i t i o n s (or

27 - \text{position}

) :

\text{L} = 15, \text{O} = 12, \text{S} = 8, \text{T} = 7

$\text{Reverse Sum} = 15 + 12 + 8 + 7 = 42

None matches 32 directly. Let's look at alternative logic:Let's find

Sum - (Number of letters \times constant)

or something similar:Let's test the reverse sum minus a constant:

42 - 10 = 32

Let's check CRAMP with reverse values:

C = 24, R = 9, A = 26, M = 14, P = 11

Reverse Sum = 24 + 9 + 26 + 14 + 11 = 84

T hi s d oes n o t re l a t ec l ose l y t o 50 v iaa s im pl es u b t r a c t i o n o f 10. L e t^{'} s t ry an o t h er p a tt er n u s in g s t an d a r d p os i t i o n s : L OST :

12 + 15 + 19 + 20 = 66

. D i g i t ss u m :

6 + 6 = 12 \neq 32

. L e t^{'} s l oo ka t s t an d a r d p os i t i o n so f v o w e l s an d co n so nan t sse p a r a t e l y : C o n so nan t so f L OST :

\text{L}(12) + \text{S}(19) + \text{T}(20) = 51

. V o w e l :

\text{O}(15)

. L e t^{'} s t ry t h e f or m u l a :

\text{Reverse positional values sum} - (\text{Number of letters} \times 2.5)

? N o . L e t^{'} sre - e x amin es t an d a r d p os i t i o n s an d s u b t r a c t so m e t hin g : L OST :

. H a l f o f 66 i s 33.

33 - 1 = 32

. CR A MP :

\text{C}(3) + \text{R}(18) + \text{A}(1) + \text{M}(13) + \text{P}(16) = 51

. H a l f o f 51 i s

25.5

, n o tw or kin g . L e t^{'} s t ry :

(\text{Sum of vowels}) \times 2 + \text{Consonants}

e t c . L OST : V o w e l

\text{O} = 15

. C o n so nan t s

= 12 + 19 + 20 = 51

. L e t^{'} s l oo ka t :

\text{Consonants sum} - \text{Vowels sum} = 51 - 15 = 36

. CR A MP : V o w e l

\text{A} = 1

. C o n so nan t s

= 3 + 18 + 13 + 16 = 50

.

\text{Consonants sum} - \text{Vowels sum} = 50 - 1 = 49

. L e t^{'} s t ry t o t a l n u mb ero f l e tt ers m u lt i pl i e d b yso m e t hin g : L e t^{'} sc h ec k t h e n u mb ero f co n so nan t s v s v o w e l s . L e t^{'} s t es t an o t h er d i rec t r u l e : S u m o f o pp os i t e f a ces / l e tt ers v a l u es : L OST o pp os i t e :

\text{O}(15) + \text{L}(12) + \text{H}(8) + \text{G}(7) = 42

. N u mb ero f l e tt ers

= 4

.

42 - (4 \times 2.5) = 32

. CR A MP o pp os i t e :

\text{X}(24) + \text{I}(9) + \text{Z}(26) + \text{N}(14) + \text{K}(11) = 84

. I f w es u b t r a c t

, w e g e t 50. N o t ma t c hin g . L e t^{'} s l oo ka t s t an d a r d v a l u es : L OST :

12 + 15 + 19 + 20 = 66

. R e v erse i t :

66 \rightarrow 6 \times 6 - 4 = 32

. CR A MP :

3 + 18 + 1 + 13 + 16 = 51

. R e v erse i t :

5 \times 1 - 4 \neq 50

. L e t^{'} sc h ec k : L OST :

(12 + 20) = 32

(S u m o ff i rs t an d l a s tl e tt er p os i t i o na l v a l u es) . L e t^{'} sc h ec k CR A MP :

(3 + 16) = 19 \neq 50

. L e t^{'} s l oo ka t re v erse p os i t i o na l v a l u es a g ain : L OST :

\text{L}=15, \text{O}=12, \text{S}=8, \text{T}=7

. S u m o ff i rs t an d l a s t re v erse v a l u es :

15 + 7 = 22

. S u m o f mi dd l ere v erse v a l u es :

12 + 8 = 20

. L e t^{'} sc h ec k s t an d a r d p os i t i o n s u m o f a lt er na t e l e tt ers : L OST :

12 + 19 = 31

;

15 + 20 = 35

. CR A MP :

\text{C}(3) + \text{A}(1) + \text{P}(16) = 20

;

\text{R}(18) + \text{M}(13) = 31

. L e t^{'} s t ry :

\text{Total positional value sum} - 34

f or L OST ?

66 - 34 = 32

. F or CR A MP :

51 - 1 = 50

. L e t^{'} sc h ec kan o t h er l o g i c : L OST :

\text{L}=12, \text{O}=15, \text{S}=19, \text{T}=20

.

(12 \times 2) + 15 + 19 + 20

n o . L e t^{'} ss u b t r a c ttw i ce t h e n u mb ero f l e tt ers :

66 - 2 \times 4 = 58

. L e t^{'} s l oo ka t re v erse v a l u ess u m : L OST :

15 + 12 + 8 + 7 = 42

. S u b t r a c t

10 \rightarrow 32

. CR A MP :

24 + 9 + 26 + 14 + 11 = 84

. L e t^{'} ssee i f w es u b t r a c t

(27 \times \text{number of vowels})

:

84 - 27 = 57

. L e t^{'} s l oo ka tt h eco d e : L OST

= 32

. N o t i ce t ha t

\text{L}(12) + \text{T}(20) = 32

. CR A MP

= 50

. N o t i ce t ha t

\text{R}(18) + \text{M}(13) + \text{P}(16) + \text{C}(3) = 50

. T ha t^{'} s t h es u m o f a ll co n so nan t s! L e t^{'} sc h ec k :

\text{C}(3) + \text{R}(18) + \text{M}(13) + \text{P}(16) = 50

. L e t^{'} sc h ec ki f t h e l o g i c i s S u m o f p os i t i o na l v a l u eso f co n so nan t so n l y : I n L OST : C o n so nan t s a re L, S, T .

\text{Sum} = 12 + 19 + 20 = 51 \neq 32

. L e t^{'} sc h ec k R e v erse p os i t i o na l v a l u eso f co n so nan t s / v o w e l s : I n L OST : V o w e l i s O . R e v erseo f O i s 12. T o t a l re v erses u mi s 42.

42 - 12 = 30

. Wha t i f t h e l o g i c i s : S u m o f re v erse p os i t i o na l v a l u eso f co n so nan t so n l y ? I n L OST : C o n so nan t s a re L, S, T . R e v erse v a l u es :

\text{L}=15, \text{S}=8, \text{T}=7

.

Sum = 15 + 8 + 7 = 30 \neq = 32

Wha t i f i t i s S u m o f s t an d a r d p os i t i o na l v a l u eso f v o w e l s + re v erseo f co n so nan t s ? L e t^{'} sc h ec k S u m o f re v erse p os i t i o na l v a l u eso f v o w e l so n l y : I n L OST : V o w e l

\text{O} = 12

. I n CR A MP : V o w e l

\text{A} = 26

. L e t^{'} s l oo ka tT o t a l s t an d a r d s u mmin u sso m e t hin g : L OST :

12+15+19+20 = 66

.

66 - 34 = 32

. CR A MP :

3+18+1+13+16 = 51

.

51 - 1 = 50

. (Here 34 an d 1 ha v e n oc l e a rre l a t i o n) . L e t^{'} s f in d an o t h erre l a t i o n : L OST :

(12 + 15) - (19 + 20) = 27 - 39 = -12

. L OST :

12 \times 15

... L e t^{'} sc h ec k t h e n u mb ero f v o w e l s an d co n so nan t s : L OST : 1 v o w e l, 3 co n so nan t s . CR A MP : 1 v o w e l, 4 co n so nan t s . L e t^{'} sc h ec k t h e n u mb ero f s t ro k esor a lp hab e t i c a l or d er p os i t i o n s . L e t^{'} s l oo ka tt h eo pt i o n v a l u es f or FR Y : 24, 18, 20, 26. St an d a r d s u m f or FR Y :

\text{F}(6) + \text{R}(18) + \text{Y}(25) = 49

. R e v erses u m f or FR Y :

\text{U}(21) + \text{I}(9) + \text{B}(2) = 32

. I f t h e p a tt er ni sre l a t e d t o t h ere v erses u m : F or L OST : R e v erses u mi s

. C o d e i s

(

42 - 10

) . F or CR A MP : R e v erses u mi s

. C o d e i s

(

84 - 34

) . F or FR Y : R e v erses u mi s

. I f w e l oo k c l ose l y a tt h es u b t r a c t i o n v a l u es :

10, 34

, t h ey d o n^{'} t f or ma c l e a rse q u e n ce . L e t^{'} s l oo ka t :

\text{Reverse Sum} - (\text{Product of number of vowels and consonants})

? L OST :

42 - (1 \times 3) = 39 \neq 32

. L e t^{'} sc h ec k :

\text{Standard Sum} - \text{Reverse Sum}

: L OST :

66 - 42 = 24

. CR A MP :

51 - 84 = -33

. L e t^{'} s l oo ka t :

(\text{Number of letters})^2

ors imi l a r : F or L OST :

l e tt ers

\rightarrow 4^2 \times 2 = 32

. F or CR A MP :

l e tt ers

\rightarrow 5^2 \times 2 = 50

. T hi s ma t c h es p er f ec tl y! L e t^{'} s v er i f y : L OST :

4 \text{ letters} \rightarrow 4^2 \times 2 = 16 \times 2 = 32

. CR A MP :

5 \text{ letters} \rightarrow 5^2 \times 2 = 25 \times 2 = 50

. A ppl y in g t h es am e l o g i c t o FR Y : FR Yha s

l e tt ers .

Code = 3^{2} \times 2 = 9 \times 2 = 18

$
The code for 'FRY' is 18.

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