In a certain code language, 'QUIET' is coded as '70', and 'TREND' is coded as '57'. How will 'TROUBLE' be coded in that language?

Let's calculate the sum of positional values of individual letters in alphabetical order (A=1, B=2, ..., Z=26):For QUIET:Q = 17, U = 21, I = 9, E = 5, T = 20$\text{Sum}=17+21+9+5+20=72$ Given code is 70, which is $\text{Sum}-2$.For TREND:T = 20, R = 18, E = 5, N = 14, D = 4$\text{Sum}=20+18+5+14+4=61$ Given code is 57, which is $\text{Sum}-4$.Let's look for a standard logic. Let's test the sum of opposite positions (27 - standard position):For QUIET:Q $\to$ 10, U $\to$ 6, I $\to$ 18, E $\to$ 22, T $\to$ 7$\text{Sum of Opposites}=10+6+18+22+7=63$. Not 70.Let's re-verify the original sum:QUIET: $\text{Sum}=72$. Code $=70$ (which is $72-\text{number of vowels}$, where vowels are U, I, E = 3? $72-3=69\ne 70$).What if the pattern is: $\text{Sum of vowels}\times 2$ or similar?Let's check: Vowels in QUIET are U(21), I(9), E(5) $\to \text{Sum}=35$. Consonants are Q(17), T(20) $\to \text{Sum}=37$. Total $=72$.Let's check another simple rule: $\text{Sum}-(\text{number of consonants})=72-2=70$.Let's check this with TREND:Consonants are T(20), R(18), N(14), D(4) $\to$ 4 consonants.$\text{Total Sum}=61$.$\text{Sum}-\text{number of consonants}=61-4=57$. This matches TREND perfectly!So, the pattern is: $\text{Total sum of alphabetical positions}-\text{Number of consonants}$.Now let's apply this rule to TROUBLE:Letters and positions: T = 20, R = 18, O = 15, U = 21, B = 2, L = 12, E = 5$\text{Total Sum}=20+18+15+21+2+12+5=93$ Consonants in TROUBLE: T, R, B, L (Total 4 consonants)$\text{Final Code}=93-4=89$