In a certain code language, 'TREE' is written as 'WWHJ', and 'LEAF' is written as 'OJDK'. How will 'BARK' be written in that language?
- AEFTP
- BGFUN
- CGDWN
- DEFUP
Solution & Step-by-step Explanation
The positional values of the letters in alphabetical order are used to determine the logic:
For 'TREE' → 'WWHJ':
T(20)+3=W(23)
R(18)+5=W(23)
E(5)+3=H(8)
E(5)+5=J(10)
The pattern is alternating additions of +3 and +5.
Let's check 'LEAF' → 'OJDK':
L(12)+3=O(15)
A(1)+4→ Let's re-verify the vowel/consonant pattern.
Alternatively, look at the positions:
L(12)+3=O(15)
E(5)+5=J(10)
A(1)+3=D(4)
F(6)+5=K(11)
So the operation is consistently +3,+5,+3,+5 across the positions.
Applying the same logic to 'BARK':
B(2)+3=E(5)
A(1)+5=F(6)
R(18)+3=U(21)
K(11)+5=P(16)
Thus, 'BARK' is coded as 'EFUP'.
For 'TREE' → 'WWHJ':
T(20)+3=W(23)
R(18)+5=W(23)
E(5)+3=H(8)
E(5)+5=J(10)
The pattern is alternating additions of +3 and +5.
Let's check 'LEAF' → 'OJDK':
L(12)+3=O(15)
A(1)+4→ Let's re-verify the vowel/consonant pattern.
Alternatively, look at the positions:
L(12)+3=O(15)
E(5)+5=J(10)
A(1)+3=D(4)
F(6)+5=K(11)
So the operation is consistently +3,+5,+3,+5 across the positions.
Applying the same logic to 'BARK':
B(2)+3=E(5)
A(1)+5=F(6)
R(18)+3=U(21)
K(11)+5=P(16)
Thus, 'BARK' is coded as 'EFUP'.