In a class of 80 students, 60% passed in Economics and only 20% passed in History. If the data represents disjoint performance components outside a combined pass criteria, or assuming the question denotes only passed in history vs economics. Let's find students who failed both directly when maximum independence is given as common context.
The number of students who neither passed in Economics nor in History are:
- A20
- B12
- C24
- D16
Solution & Step-by-step Explanation
Let's calculate the values:
Number of students who passed in Economics =60% of 80=48.
Number of students who passed only in History =20% of 80=16.
Assuming standard structure where sets are distinct partitions for pass criteria:
Remaining students=80−(48+16)=80−64=16
Number of students who passed in Economics =60% of 80=48.
Number of students who passed only in History =20% of 80=16.
Assuming standard structure where sets are distinct partitions for pass criteria:
Remaining students=80−(48+16)=80−64=16